Explain the product of the reaction CH_3CH=CH | vedclass

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(B) The reaction of $CH_3CH=CH_2$ with $HCl$ in the presence of peroxide follows Markovnikov's rule to form $2$-chloropropane $(CH_3CHClCH_3)$.Anti-Ma

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$2$-Chloropropane

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(B) The reaction of $CH_3CH=CH_2$ with $HCl$ in the presence of peroxide follows Markovnikov's rule to form $2$-chloropropane $(CH_3CHClCH_3)$.Anti-Markovnikov addition (peroxide effect) is only observed with $HBr$ and not with $HCl$ or $HI$.This is because the $H-Cl$ bond is very strong $(403.5 \ kJ \ mol^{-1})$,and the peroxide free radicals are unable to abstract a hydrogen atom from $HCl$ to initiate the chain reaction.

Explain the product of the reaction $CH_3CH=CH_2 + HCl \xrightarrow{\text{peroxide}}$

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